X^2-5x+0.75=0

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Solution for X^2-5x+0.75=0 equation: 



X^2-5X+0.75=0

a = 1; b = -5; c = +0.75;
Δ = b2-4ac
Δ = -52-4·1·0.75
Δ = 22
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{22}}{2*1}=\frac{5-\sqrt{22}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{22}}{2*1}=\frac{5+\sqrt{22}}{2}
$

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